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Aaron Rodgers ranked No. 10 in NFL’s ‘Top 100’

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GREEN BAY - Packers QB Aaron Rodgers came in at No. 10 on the NFL Network’s “Top 100 Players of 2018,” as the list’s top 10 were announced Monday night.

It’s Rodgers’ sixth appearance in the top 10 and eighth career mention on the list. He was ranked No. 1 in 2012 and No. 2 in 2015, his highest rankings following his two MVP seasons.

He also has ranked sixth three times (2013, ’16, ’17) as well as 11th in both 2011 and 2014.

Rodgers played in just seven games in 2017 due to a broken right collarbone. He completed 64.7 percent of his passes, with 16 touchdowns against six interceptions, for a 97.2 passer rating.

The Packers were 4-1 when Rodgers went down early in the game at Minnesota in Week 6. He missed the rest of that game, plus the next seven, before returning in Week 15 at Carolina to try to keep the Packers’ playoff hopes alive.

The Packers were 7-6 at that point, but a loss dropped them to 7-7 and out of playoff contention. Rodgers then sat out the team’s final two contests.

He is the sixth Packers player to make this year’s “Top 100,” following safety Ha Ha Clinton Dix (No. 100), defensive tackle Mike Daniels (No. 93), left tackle David Bakhtiari (No. 91), tight end Jimmy Graham (No. 89) and wide receiver Davante Adams (No. 45).

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